- 1. A train 100 m long is running at the speed of 30 km / hr. Find the time taken by it to pass a man standing near the railway line in seconds

A.5 sec

B.6 sec

C.7 sec

D.8 sec

Answer & Explanation

Answer: Option B

Explanation:**Speed of the train = (60 x 5/18m / sec = 50/3 m/ sec.**

Distance moved in passing the standing man = 100 m.

Required time taken = 100/(50/3) = (100 ×(3/50)) sec =6 sec

Distance moved in passing the standing man = 100 m.

Required time taken = 100/(50/3) = (100 ×(3/50)) sec =6 sec

- 2. A train 200 m long is running with a speed of 54 kmph. In what will it pass a car whose speed at 36 kmph in the direction opposite to that in which the train is going

A.8 sec

B.10 sec

C.12 sec

D.14 sec

Answer & Explanation

Answer: Option A

Explanation:**Speed of the train relative to man = (54 + 36) kmph**

= 90 ×5/18 m/sec = 25 m/sec.

Time taken by the train to cross the car = Time taken by it to cover 200 m

at 25 m

= 90 ×5/18 m/sec = 25 m/sec.

Time taken by the train to cross the car = Time taken by it to cover 200 m

at 25 m

*/*sec = (200 ×1/25) sec = 8 sec- 3. Two trains 120 meters and 150 meters long are running in the same direction with speeds of 92 km/hr, 56km/hr. In how much time will the first train cross the second

A.37 sec

B.22 sec

C.27 sec

D.35sec

Answer & Explanation

Answer: Option C

Explanation:**Relative speed of the trains = (92 - 56) km/hr = 36 km/hr**

= (36× 5/18) m/sec = 10 m/sec.

Time taken by the trains to cross each other

= Time taken to cover (120 + 150) m at 10 m

= (36× 5/18) m/sec = 10 m/sec.

Time taken by the trains to cross each other

= Time taken to cover (120 + 150) m at 10 m

*/*sec = (270/10) sec = 27 sec.- 4. A train is moving at a speed of 132 km/hr. If the length of the train is 100 meters, how long will it take to cross a railway platform 175 meters long

A.6 ½ sec

B.7 ½ sec

C.8 sec

D.8 ½ sec

Answer & Explanation

Answer: Option B

Explanation:**Speed of train = 132 ×(5/18) m/sec = 110/3 m/sec.**

Distance covered in passing the platform = (100 + 175) m = 275 m.

Time taken =275 ×(3/110) sec =15/2 sec = 7 ½ sec

Distance covered in passing the platform = (100 + 175) m = 275 m.

Time taken =275 ×(3/110) sec =15/2 sec = 7 ½ sec

- 5. A man is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of the train and its speed

A.50 km

B.52 km

C.54 km

D.56 km

Answer & Explanation

Answer: Option C

Explanation:**Let the length of the train be x meters,**

Then, the train covers x meters in 8 seconds and (x + 180) meters in 20 sec

x/8=(x+180)/20 ⇔ 20x = 8 (x + 180) <=> x = 120

Length of the train = 120 m.

Speed of the train = (120/8)m

Then, the train covers x meters in 8 seconds and (x + 180) meters in 20 sec

x/8=(x+180)/20 ⇔ 20x = 8 (x + 180) <=> x = 120

Length of the train = 120 m.

Speed of the train = (120/8)m

*/*sec = m*/*sec = (15 ×18/5)kmph = 54 km**To whom this Problems on Trains Questions and Answers section is beneficial?**

Students can learn and improve on their skillset for using Verbal Ability effectively and can also prepare for competitive examinations like...

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